Physics, asked by rayangate16, 1 month ago

Calculate the velocity of proton moving in a circular path of radius 8.0cm in a plane perpendicular to a 1.5T magnetic field

Answers

Answered by Anonymous
10

SOLUTION'-

  • Here, the magnetic force supplies the centripetal force Fc = mv2/r. Noting that sin θ = 1, we see that F = qvB.
  • Magnetic force can cause a charged particle to move in a circular or spiral path. Cosmic rays are energetic charged particles in outer space, some of which approach the Earth. They can be forced into spiral paths by the Earth’s magnetic field. Protons in giant accelerators are kept in a circular path by magnetic force. The bubble chamber photograph in Figure 1 shows charged particles moving in such curved paths. The curved paths of charged particles in magnetic fields are the basis of a number of phenomena and can even be used analytically, such as in a mass spectrometer.
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