Question

Calculate the velocity of the 2.0 kg mass just before it hits the rocks when it is dropped from a height of 16 m above the surface of the rocks. Give the unit.

Velocity : __
Unit : __​

Answer 1

Answer:

2as=vf^2-vi^2

vi^2=0

a=g

s=h

2gh=vf^2

Vf=(2gh)^1/2

Vf=2×9.8×16

Vf=313.6m/s

Answer 2

Given

Here, mass = 2 kg

u (initial velocity) = 0 m/s

g (acceleration due to gravity) = 10 m/s²

h (height) = 16 m

To Find

v (final velocity)

Answer with explanation

We know that 2gh = v² - u²

Since u = 0, u² = 0² = 0

2 × 10 m/s² × 16 m = v² - 0

320 m²/s² = v²

v = √(320 m²/s²)

v = 17.8 m/s