calculate the velocity of the electron in Bhor first orbit of hydrogen atom
Answers
Answered by
1
Answer:
the velocity of the electron in the first Bohr orbit of the hydrogen atom is 2.18×106m/sec.
Explanation:
Given parameters
n=1
h=6.626×10−26
m=9.1×10−31kg
The velocity of an electron in the first Bohr orbit of H- atom
mvr = nh/2π
v = nh/2πmr
∴ v = (1 × 6.626×10−26)/ (2 × 3.14 × 91 × 0−31 × 0.529 × 0−10)
v = 2.18×106ms−1.
Answered by
1
Answer:
The answer is 0
Explanation:
because valency is the no. of electrons losed or gained to complete the outermost shell
.
.
.
I hope it helped you
Similar questions