Question

Calculate the velocity of the electron in the third orbit of hydrogen atom

Answer 1

$0.7 \times {10}^{6}$

Explanation:

we know...

velocity of electron =

$2.2 \times {10}^{6} \frac{z}{n} \:$

where z is atomic number, and n is orbit number.

so velocity of electron in 3 orbit =

$2.2 \times {10}^{6} \times \frac{1}{3}$

=>

$0.7 \times {10}^{6} \frac{m}{s}$

hope it helps...;-)

Answer 2

The radius of 3rd orbit of H atom can be calculated as,

$V_{n} =\sqrt{\frac{Ze^{2} }{mrn} }$

$For\:an\:Electron,e=4.80\:\times\:10^{-10}\:esu$

                             

$m=9.1\:\times\:10^{-28}\:g$

$Radius\:of\:3rd\:Orbit=r_{1}\:\times\:n^{2}  =0.529\:\times\:10^{-8}\:\times\:9$

$V_{n}=\sqrt{\frac{1\:\times\:(4.803\:\times\:10^{-10})^{2}  }{9.1\:\times\:10^{-28\:\times\:0.529\:\times\:10^{-8}\:\times\:9 } } }$

$V_{n}=7.29\:\times\:10^{7}\:m/sec$