calculate the velocity of the particle of mass 0.1 MG which is associated with a wavelength of 3.3 into 10 raise to the power - 29 meter
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Given conditions ⇒
Mass of the Particles = 0.1 Mg.
= 0.1 × 10⁶ g.
= 10⁵ g.
Wavelength of the Particles = 3.3 × 10⁻²⁹ m.
Using the de-broglie relation,
λ = h/mv.
h = 6.62 × 10⁻³⁴ J-s.
3.3 × 10⁻²⁹ = 6.62 × 10⁻³⁴/(10⁵ × v)
3.3 × 10⁻²⁴ × v = 6.62 × 10⁻³⁴
∴ v = 2.006 × 10⁻¹⁰ m/s.
Hence, the velocity of the Particles is 2.006 × 10⁻¹⁰ m/s.
Hope it helps.
Mass of the Particles = 0.1 Mg.
= 0.1 × 10⁶ g.
= 10⁵ g.
Wavelength of the Particles = 3.3 × 10⁻²⁹ m.
Using the de-broglie relation,
λ = h/mv.
h = 6.62 × 10⁻³⁴ J-s.
3.3 × 10⁻²⁹ = 6.62 × 10⁻³⁴/(10⁵ × v)
3.3 × 10⁻²⁴ × v = 6.62 × 10⁻³⁴
∴ v = 2.006 × 10⁻¹⁰ m/s.
Hence, the velocity of the Particles is 2.006 × 10⁻¹⁰ m/s.
Hope it helps.
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