Question

)Calculate the vertical height through which a body of mass 10 kg is lifted when 1470 J of work is done in lifting it.[g=9.8 m/s2]

Answer 1

GIVEN:

work done= 1470J

mass= 10kg

g=9.8

FORMULA:

$w = f.s$

$w = mg \times s$

$s = \frac{w}{mg}$

$s = \frac{1470}{98}$

$s = 15m$

I hope this helps ( ╹▽╹ )