Question

calculate the view length for the transition in the balmar serise shortest view length​

Answer 1

Answer:

Wavelength in the Balmer series of H-atom:

λ

1

=1.097×10

7

×(

n

1

2

1

−

n

2

2

1

) m

−1

For shortest wavelength in the Balmer series: n

1

=2 n

2

=∞

∴

λ

min

1

=1.097×10

7

×(

2

2

1

−

∞

1

)m

−1

λ

min

=

1.097×10

7

4

m =3.646×10

−7

m=364.6 nm

This wavelength lies in the ultraviolet region.