Calculate the viscous force on a water
drop of radius 0.1 mm falling through air
of n = 1.8*10*-5Kgm-1s-1 with constant velocity 0.15 cm/s
Answers
Answered by
1
Here, r=0.1 mm = 0.01cm,
v = 0.15 cm/s
η = 18 × 10^-5 poise.
According to stokes law, force of viscosity on rain drop is
F = 6πηrv
= 6 × 3.142 × 18 × 10^-5 × 0.01 × 0.15
= 0.00000509004 dyne = 5.09 × 10^-6 dyne
Similar questions