Question

Calculate the volume and mass of carbon-di-oxide liberated when 500g of calcium carbonate is heated at STP​

Answer 1

Answer:

112 litres and 220 gms liberared

Answer 2

The volume and mass of carbon-dioxide liberated when 500g of calcium carbonate is heated at STP​ are 112 L and 220 g respectively.

Explanation:

$CaCO_3\rightarrow CaO+CO_2$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of calcium carbonate}=\frac{500g}{100g/mol}=5moles$

According to stoichiometry:

1 mole of  gives 1 mole of $CO_2$

Thus 5 moles of  $CaCO_3$ will give CO_2=$\frac{1}{1}\times 5=5$moles of $CO_2$

Mass of $CO_2=moles\times {\text {molar mass}}=5mol\times 44g/mol=220g$

Using ideal gas equation at STP:

$PV=nRT$

$1atm\times V=5mol\times 0.0821Latm/Kmol\times 273K$

$V=112L$

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