Chemistry, asked by bharatkattamuri, 7 months ago

calculate the volume and number of molecules of co2 liberated at STP if caco3 is treated with 36.5 gram of HCL​

Answers

Answered by DrNykterstein
3

Given :-

CO₂ is liberated at STP if CaCO₃ is treated with 36.5 g of HCl

To Find :-

Volume and number of molecules of CO₂

Solution :-

First, Let us write the balanced chemical equation for the given chemical reaction.

CaCO₃ + 2HCl CaCl₂ + H₂O + CO₂

From the balanced chemical reaction, It is clear that,

2 mole of HCL when reacted with 1 mole of CaCO₃ gives 1 mole of CO₂

We have

  • Molar Mass of HCL = 35.5 + 1 = 36.5 g
  • Given mass of HCL = 36.5 g

So,

⇒ Num. of mole = Mass given / Molar mass

⇒ Num. of mole = 36.5 / 36.5

Num. of mole = 1 mol

Since, 2 mole of HCl produces 1 mole of CO₂ so 1 mole of HCl will produce 0.5 mole of CO₂

Now,

⇒ Num. of moles = Volume / 22.4

⇒ 0.5 = Volume / 22.4

⇒ Volume = 22.4 × 0.5

Volume = 11.2 litres

Also, We know, 1 mole of any molecule has 6.022 × 10²³ molecules so,

⇒ Num. of molecules = moles × Avogadro Number

⇒ Num. of molecules = 0.5 × 6.022 × 10²³

⇒ Num. of molecules = 3.011 × 10²³ molecules

Hence,

  • Volume = 11.2 litres
  • Number of molecules = 3.011 × 10²³
Answered by Anonymous
1

Explanation:

Given :-

▪ CO₂ is liberated at STP if CaCO₃ is treated with 36.5 g of HCl

To Find :-

▪ Volume and number of molecules of CO₂

Solution :-

First, Let us write the balanced chemical equation for the given chemical reaction.

CaCO₃ + 2HCl ➞ CaCl₂ + H₂O + CO₂

From the balanced chemical reaction, It is clear that,

2 mole of HCL when reacted with 1 mole of CaCO₃ gives 1 mole of CO₂

We have

Molar Mass of HCL = 35.5 + 1 = 36.5 g

Given mass of HCL = 36.5 g

So,

⇒ Num. of mole = Mass given / Molar mass

⇒ Num. of mole = 36.5 / 36.5

⇒ Num. of mole = 1 mol

Since, 2 mole of HCl produces 1 mole of CO₂ so 1 mole of HCl will produce 0.5 mole of CO₂

Now,

⇒ Num. of moles = Volume / 22.4

⇒ 0.5 = Volume / 22.4

⇒ Volume = 22.4 × 0.5

⇒ Volume = 11.2 litres

Also, We know, 1 mole of any molecule has 6.022 × 10²³ molecules so,

⇒ Num. of molecules = moles × Avogadro Number

⇒ Num. of molecules = 0.5 × 6.022 × 10²³

⇒ Num. of molecules = 3.011 × 10²³ molecules

Hence,

Volume = 11.2 litres

Number of molecules = 3.011 × 10²³

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