Question

calculate the volume at NTP occupied by 10^21 molecules of oxygen ​

Answer 1

here is the answer

volume at NTP occupied by 10^21 molecules of Oxygen

No. of moles = No. of molecules / N .... ( N is avagadro number....)...

No. of moles = 10^21 / 6 × 10^23 ...

= 1/6 × 10^-2 = 0.0016 ...

Volume at STP = moles × 22.4

= 0.0016 × 22.4 = 0.037 L ...

Answer 2

Answer :

Given molecules of $O_2$ = $10^{21}$

Molecules in 1 mole of $O_2$ = $6.022\times10^{23}$

Volume occupied by $6.022\times10^{23}$ molecules of $O_2$ = 22.4 L

Volume occupied by 1 molecule of $O_2$ = $\dfrac{22.4}{6.022\times10^{23}}$

Volume occupied by $10^{21}$ molecules of $O_2$ = $\dfrac{22.4}{6.022\times10^{23}}\times10^{21}$

=$\dfrac{11.2}{3.011}\times10^{-2}$

=$0.036L$

=$3.6\times10^{-2}L$