Question

calculate the volume at NTP occupied by 6.25 g of nitrogen ?

Answer 1

Answer:

5.26 L

Explanation:

NTP refers to Normal temperature and pressure, ie

Pressure, P = 1 atm= 1 x $10^{5} Pa$

Temperature, T = 20°C = 273 + 20 = 293K

we know that, PV= mRT

where P is pressure, V is volume , m is mass & T is temperature

R is the gas constant, ie R =287 J/kgK

Therefore,

V= (mRT)/P

given, m = 6.25g= 0.00625kg

V = (0.00625×287×293)/ (1×$10^{5}$

= 5.26 × $10^{-3}$ m³

= 5.26 L