Question

Calculate the volume at ntp occupied by 6.25g of nitrogen

Answer 1

28 gms (1 mole) occupies 22.4 litre

So, 6.25 gms occupy x litre (suppose)

So,

x = 22.4 × 6.25 / 28

= 5 litre

Answer 2

The volume occupied by NTP is 4.99 L

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of nitrogen gas = 6.25 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in above equation, we get:

$\text{Moles of nitrogen gas}=\frac{6.25g}{28g/mol}=0.223mol$

At NTP:

1 mole of a gas occupies 22.4 L of volume

So, 0.223 moles of nitrogen gas will occupy a volume of = $\frac{22.4L}{1mol}\times 0.223mol=4.99L$ of volume

Learn more about NTP:

https://brainly.in/question/4493420

https://brainly.com/question/7250374

#learnwithbrainly