Question

calculate :

The volume at s.t.p. occupied by a gas 'Q' originally occuping 153.7cm3 at 287K and 750mm.pressure.

[Vapour pressure of gas 'Q' at 287K is 12mm of Hg].

Answer 1

The second Volume is 146.6 cm^3

Explanation:

Given data:

• Volume of gas = 153.7 cm^3
• Temperature "T" = 287 K
• Pressure "P" = 750 mm

P1V1/ T1 = P2V2 / T2

We have  p1 = 750 + vapour pressure of gas at 287 K

= (750 + 12) mm of Hg = 762 mm of Hg  

V1 = 153.7 cm^3 and T1 = 287 K

p2 = 760 mm of Hg , T2 = 273 K    

(As STP conditions are 1 atm pressure which is equal to 760 mm of Hg and 273K temperature)

And V2 = ?

Therefore  V2 =  (p1V1) / T1 X (T2 / p2)

                       =  (762 X 153.7 X 273) / ( 287 X 760)

                        = 146.6 cm^3

Hence the second Volume is 146.6 cm^3.

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Calculate the volume of gas X at S.T.P. if it occupies 380 litres at 300 K and 70 cm of mercury. ?

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