Question

Calculate the volume at s.t.p occupied by
$6.023 \times 10 {}^{22}$
molecules of a Gas X.

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Answer 1

Answer:

2.24 liters

Explanation:

1 mole = 6.023 x 10²³ molecules

Therefore, 6.023 x 10²² molecules = 0.1 moles

At S.T.P,

1 mole occupies 22.4 liters

So,

0.1 moles will occupy:

1/10 x 22.4

= 2.24 liters

Hope this helps!