Question

Calculate the volume at stp occupied by 10^21 molecules of oxygen

Answer 1

Solution :

⏭ Given:

✏ No. of molecules of oxygen = $10^{21}$

⏭ To Find:

✏ Volume occupied by the molecules at STP

⏭ Concept:

✏ 6.022 × $10^{23}$ molecules (one mole) occupied 22.4 L volume at STP

⏭ Conversation:

✏ 22.4 L = 22400 mL

($\because$ 1 L = 1000 mL)

⏭ Calculation:

$\implies \sf \: V{ \tiny{O_2}} = \frac{ {10}^{21} \times 22400 }{6.022 \times {10}^{23} } \\ \\ \implies \sf \: V{ \tiny{O_2}} = \frac{3719.6}{100} \\ \\ \implies \: \boxed{ \bold{ \sf{ \purple{V{ \tiny{O_2}} = 37.19 \: mL}}}} \: \orange{ \bigstar}$