Question

Calculate the volume at stp occupied by 10 21 molecules of oxygen

Answer 1

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No. of moles = No. of molecules / N .... ( N is avagadro number....)...

No. of moles = 10^21 / 6 × 10^23 ...
= 1/6 × 10^-2 = 0.0016 ...

Volume at STP = moles × 22.4
= 0.0016 × 22.4 = 0.037 L ...

Answer 2

According to the question;

No. of molecules of oxygen = $10^{21}$

The volume occupied by the molecules at STP

6.022 × $10^{23}$ molecules (one mole) occupied 22.4 L volume at STP

22.4 L = 22400 mL ( 1 L = 1000 mL)

now,

$Volume = \frac{10^{21} * 22400 }{6.022 * 10^{23} }$

$= \frac{3719.6}{100} \\=37.196$

The volume at STP occupied by 10²¹ molecules of oxygen is 37.196.

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