calculate the volume at STP occupied by 1021
molecules of Oxygen?
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1x10^21/6.02x10^23 =1/602
Moles = volume/24dm^3
Moles x 24 = volume = 24 x 1/602 = 0.037209dm^3=37.21cm^3
Moles = volume/24dm^3
Moles x 24 = volume = 24 x 1/602 = 0.037209dm^3=37.21cm^3
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