Question

calculate the volume at STP occupied by 14g of nitrogen .

Answer 1

28 gm(1mol) of nitrogen has a volume of 22.4L
Therefore, 14gm of nitrogen occupies (22.4/2) =11.2L

Answer 2

The volume of nitrogen is 11.2 L

Solution:

Here STP stands for Standard Temperature and Pressure.

At STP, 1 mole of Nitrogen $(N_2)$ = 28 g  

And the Nitrogen $(N_2)$ which occupies a volume of 22.4 L  

Therefore, by using unit method,

$14 \ grams \ of \ N_2 \ occupy = \frac{22.4}{2} = 11.2 \ L$

We have taken the approach of unit method in this solution and it helped us reach the solution quickly. Whenever you encounter any such question, try using unit method to save time.