Question

calculate the volume at STP OCCUPIED by 240gm of SO2

Answer 1

volume = 84L
no of moles= given mass/gram molecular mass
=240/64
3.75
no of moles=given volume/22.4L at stp
3.75=x/22.4
x=22.4*3.75
volume= 84L

hope it helps u

Answer 2

Answer: The volume occupied by the given amount of sulfur dioxide will be 84 L.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sulfur dioxide gas = 240 g

Molar mass of sulfur dioxide gas = 64 g/mol

Putting values in above equation, we get:

$\text{Moles of sulfur dioxide gas}=\frac{240g}{64g/mol}=3.75mol$

At STP:

1 mole of a gas occupies 22.4 L of volume.

So, 3.75 moles of sulfur dioxide gas will occupy = $\frac{22.4L}{1mol}\times 3.75mol=84L$ of volume.

Hence, the volume occupied by the given amount of sulfur dioxide will be 84 L.