Question

Calculate the volume by 28 u nitrogen gas

Answer 1

1. 28 u represents the molecular mass of N2gas.
Now, 1 mole of a gas contains 6.022 x 1023molecules.

Volume occupied by 1 mole(6.022 x 1023  molecules) of N2 gas at STP = 22.4 L
  Volume occupied by 1 molecule of N2 gas at STP = 22.4 L/6.022 x1023
  = 3.72 x 10-23 L

2. 28 g represent molar mass of N2 gas
Now,
Volume occupied by 1 mole of N2 gas at STP = 22.4 L

Answer 2

Nitrogen exists as N2 gas in the atmospheric.

So, molar mass of N2 = 28 g/mol


Now, number of moles is

n = given mass/molar mass
So, n= 28/28 = 1 mol

Now, we know that one mole of any gas occupies 22.4 L volume at STP condition.

So, the volume of 28 g N2 (1 mole) gas will also be 22.4 L at STP conditions.