calculate the volume in dm3 occupied by 60.0g of ethane at stp
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Answer:
No. of moles in 60 g ethane are = 60/30
= 2 moles
in 1 mole 22.4 L is present at stp
so
in 2 moles = 2*22.4
= 44.8 L
1 L = 1 dm3
44.8 L = 44.8 dm3
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