Question

Calculate the volume in dm3 occupied by 60.0g of ethane of stp

Answer 1

Answer :

Mass of ethane = 60g

We have to find volume of the given amount of ethane at STP$.$

★ Molecular formula :

• C₂H₆

★ Molar mass :

⭆ 2(C) + 6(H)

⭆ 2(12) + 6(1)

⭆ 24 + 6

⭆ 30 g/mol

∴ 30 g of ethane occupies 22.4L volume at STP

Volume occupied by 60g of ethane at STP,

• V = 60/30 × 22.4
• V = 2 × 22.4
• V = 44.8 L

★ Remember :

➠ 1m³ = 1000L

➠ 1dm³ = 1L

➠ 1cm³ = 1mL

∴ Volume of ethane at STP = 44.8dm³

HOPE IT HELPS

Answer 2

Volume of 60 g of Ethane at STP:

• Moles of Ethane = 60/30 = 2 moles.

Now, we know that:

• 1 mole of gas occupies 22.4 litres volume at STP.

So, 2 moles of Ethane will occupy :

$= 22.4 \times 2 = 44.8 \: litres$

• Now, 1 litre = 1 dm³ (please remember this conversion).

• So, volume of Ethane = 44.8 dm³.