Calculate the volume in litres occupied by 7.40 gram of ammonia at stp
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Answer:
9.75L(approx.)
Explanation:
1 mole occupy 22.4L at stp.
no.of moles of ammonia=mass÷molar mass
=7.40÷17
=0.43
hence,volume occupied by 7.40g of ammonia at stp=22.4L×0.43
=9.75L
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