Question

calculate the volume in litres occupied by the 8 gram of oxygen at

Answer 1

volume of 16 grams of oxygen is 22.4 litres
volume of 8 grams of oxygen is 11.2 litres

Answer 2

Molecular weight of oxygen = 32 g

32 g of oxygen occupies 22.4 L volume at STP

8 g of oxygen will occupy volume = (8 × 22.4) / 32 = 5.6 L

∴ Volume occupied by 8 g of oxygen at STP is 5.6 litres