Question

Calculate the volume (in mL) of 0.100M calcium chloride needed to produce 1.00g of calcium carbonate.
molar mass of calcuim carbonate = 100.09
What is the volume of calcium chloride?

Answer 1

Answer:

0.1×1000=100mL.

Explanation:

To get the volume of CaCl2 we need to find the number of moles it will have firstly.

So using a mole-mass relationship between CaCl2 and CaCO3 we have;

1mole of CaCl2 produces 100.09g of CaCO3

The the amount of CaCl2 that'll produce 1g of CaCO3= 1×1/100.09=0.01mole.

To get our volume, we'll use the formula; n=CV where; n=number of mole,C=concentration and V=volume in dm^3 or liter.

Making volume subject of the formula we have; V=n/C

V=0.01/0.1=0.1L.

But since the answer is required to be in mL

So we have 0.1×1000=100mL.

Answer 2

we have to find the volume of 0.1 M calcium chloride needed to produce 1g of calcium carbonate.

solution : mass of calcium carbonate = 1 g

molar mass of calcium carbonate = 100.09  g/mol

so no of moles of calcium carbonate = mass/molar mass

= $\frac{1g}{100.09g/mol}$

= 0.01 mol

reaction of sodium carbonate and calcium chloride is given,

Na₂CO₃ + CaCl₂ ⇒  CaCO₃ + 2NaCl

here you see, one mole of calcium chloride reacts with one mole of sodium carbonate to form one mole of calcium carbonate and two moles of sodium chloride.

∵ one mole of CaCl₂ = one mole of CaCO₃

∴  0.01 mol of f CaCl₂ = 0.01 mol of CaCO₃

molarity of the calcium chloride = 0.1 M

we know, molarity = no of moles of solute/volume of solution

volume of solution = 0.01 mol/0.1 M  = 0.1 L = 100 mL

therefore the volume of 0.1 M calcium chloride is 100 mL.