Question

calculate
the
volume

mass
and
number
of
molecules of hydrogen liberated when 92
gram of sodium reacts with excess
of water at STP
[When Naz23U,0 = 16U H=10​

Answer 1

As per the balanced equation

46 g of of Na gives 2 g of hydrogen.

230 g of Na gives------ ? g of hydrogen.

230g x 2g / 46 g = 10g of Hydrogen.

1 gram molar mass of any gas at STP i.e., standard temperature 273 K and standard pressure 1 bar, occupies 22.4 litres known as gram molar volume.

2.0 g of hydrogen occupies 22.4 litres at STP.

10.0 g of hydrogen occupies------ ? litres at STP.

10.0 g x 22.4 litres / 2.0 g = 112 litres

2 g of hydrogen i.e., 1 mole of H2 contains 6.02 x {{10}^{23}} (H molecules 10 g of hydrogen contain ?