Question

calculate the volume, mass and number of Molecules of hydro zen librated. when 460 gm. of sodium reacts with excess of water at STP (atomic mass of Na - 23 u, 0=16u and H=1u). The balanced equation for the above reactions is a 2 Na 2H²o → 2 NO OH + H₂ ​

Answer 1

2Na+2H₂O⁻⁻⁻⁻2NaOH+H₂

so 46 g of Na reacts with water to give 22.4 L of H₂

so 230g of Na reacts with water to give 22.4X5=112 L of H₂

112 L of H₂=112/22.4=5 moles of H₂

mass of H₂ released=5X2=10g

number of molecules=5x6.023x10^{23}10

23

=30.115X10^{23}10

23

give as brainliest please