Question

calculate the volume o f 0.5 M OF SOLUTION NEUTRILIZED BY 200 ML OF 1 M HCL SOLUTION IN WATER

Answer 1

Answer:

Correct option is

B

0.6M

M=

V

1

+V

2

(V

1

×M

1

)+(V

2

×M

2

)

M=

800 mL + 200 mL

( 800 mL × 0.5 mol/L)+( 200 mL × 1 mol/L)

= 0.6 M

Hence, option B is correct.