Question

calculate the volume occupied at stp by 80.0g of oxygen

Answer 1

Pv=nrt

V=2.5×0.0821×273

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Answer 2

$\huge{\texbf\red{ANSWER }}}$

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$\huge{\texbf\red{GIVEN }}}$

Mass of oxygen = 80g

$\huge{\texbf\red{REQUIRED }}}$

Volume of oxygen at STP = ?

$\huge{\texbf\red{SOLUTION }}}$

First of all find moles of Oxygen

Moles of oxygen = mass /molar mass

Molar mass of O2 =16×2=32g/mol

Moles of Oxygen = 80 / 32

Moles of oxygen =2.5mol

Now

Moles of oxygen = Volume of oxygen /Volume atSTP

Volume of oxygen = Moles × Volume at STP

Volume of oxygen = 2.5 × 22.4

Volume of Oxygen = 56 dm^3

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