Question

Calculate the volume occupied by 0.75 moles of nitrogen.​

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Moles of Nitrogen = Weight / Molar mass= 7 g / (28 g/mol)= 0.25 molPressure = 750 mm Hg= (750/760) atm ………[∵ 1 atm = 760 mm Hg]= 75/76 atmFrom ideal gas equationV= PnRT = (75/76atm)0.25mol×0.0821atm.L/(molK)) ×300K=6.2396 litersThe volume occupied by the gas is 6.2396 litres