Calculate the volume occupied by 1.7 g of H2S at STP. its urgent
Answers
Answered by
9
Answer:
1.12l
Explanation:
no of moles =volume / 22.4
therefore,
# volume =no of moles *22.4
no of moles =1.7/2+32
= 0.05moles
volume= 0.05*22.4
= 1.12liters
therefore
volume of 1.7g Of H²S at STP is 1.12 liters
Answered by
2
Answer:
1.12 L
Explanation:
at stp
1mole=22.4L
34g(H2S mass in g )=22.4L
1.7g=xL
(34)×(x)=(22.4)×(1.7)
x= (22.4×1.7)÷34
x=1.12L
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