Question

Calculate the volume occupied by 1 mole atom of (i) monoatomic gas, and (ii) diatomic gas at

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Answer 1

Explanation:

We know that

1 mole of gas occupies 22.4 L at NTP 1 mole of O2 gas occupies 22.4 L at NTP O2 contains 2 moles of oxygen atom.

Hence 2 moles of oxygen atom occupies 22.4 L at NTP Mole = Volume / 22.4 Therefore, 1 mole of oxygen atom contains 22.4 / 2 = 11.2 L at NTP.

Answer 2

Answer:

Mole=22.4Volume(At STP)

So according to this formula 1 mole of gas occupies 22.4 litres at STP

Suppose diatomic gas is O2

So,

1 mole of O2 gas occupies 22.4 litres at STP