Calculate the volume occupied by 1 x10²³ molecules of H2S.
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Answer:
1.12 L
Explanation:
at stp
1mole=22.4L
34g(H2S mass in g )=22.4L
1.7g=xL
(34)×(x)=(22.4)×(1.7)
x= (22.4×1.7)÷34
x=1.12L
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