Question

Calculate the volume occupied by 10^22 molecules of gas at 300k and 760 atm pressure

Answer 1

No of moles present in 10^22 molecules = 10^22/6*10^23 = 1.66*10^-2

PV = nRT
V = nRT/P
R = 0.0821 L atm/K mol

On substituting and solving,
V = 0.00051 L

* Kindly check the value of pressure, it should have been 760mmHg, if not the answer above should be right

Answer 2

Answer:

The volume of the gas is 0.573 mL.

Explanation:

Molecules of gases = $10^{22}$

Mole of gases =$\frac{10^{22}}{6.022\times 10^{23}}=0.0166 mol$

Pressure of the gas = 760 atm

Temperature of the gas = 300 K

Using ideal gas equation:

$PV=nRT$

$760 atm\times V=0.0166 mol\times 0.0820 atm l/mol K\times 300 K$

V =0.000537 L=0.537 mL

The volume of the gas is 0.573 mL.