Calculate the volume occupied by 10 moles of methane at STP conditions?
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CHEMISTRY CONVERSION
Hailey R. asked • 05/11/17
Calculate the volume occupied by 16.5 of methane @STP
Calculate the volume occupied by 16.5 g of methane at STP
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Kendra F. answered • 05/11/17
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One mole of an ideal gas will occupy a volume of 22.4 liters at STP. Standard Temperature and Pressure, "STP" is 0°C (273.15 K) and one atmosphere pressure (101,325 Pa). You can plug these into the Ideal Gas Law to solve for which ever quantity is being varied.
Ideal Gas Law
PV = nRT
In this problem, you're given mass and must find volume. So first calculate the mole of ideal gas you have. I will assume that's supposed to be 16.5 grams. Make sure to always include units in the questions and solutions.
16.5 g CH4
Molecular weight of methane = 1*(12 g/mol C) + 4*(1 g/mol H) = 16 g/mol CH4
(16.5 g)/(16 g/mol) = 1.03 mol methane
That's pretty close to 1 mole which coincides with our other STP conditions so the solution will be very close to 22.4 L
At STP the Ideal Gas Law can be written as;
V = 0.022414n
by plugging in the values for R, P and T at STP. Volume is in cubic meters (mL)
V = 0.022414(1.03 mol methane) = 0.02311 mL
0.02311 mL * 1000mL/L = 23.1 L Methane
Answer:
the above answer is wrong bitch
right answer
10 × 22.4 =224 l thats is it no need to paste an paragraph here