Question

Calculate the volume occupied by 2.0 mole of N2 at 200 K and 8.21 atm pressure,
if (Pc*Vc)/(R*Tc) = 3/8 and (Pr*Vr)/Tr=2.4​

Answer 1

Explanation:

First, we will calculate the volume occupied by two moles of nitrogen at STP. We know that one mole of every gas occupies a volume of 22.4 litres at STP. Therefore volume occupied by 2 moles of nitrogen at STP will be 2 X 22.4 = 44.8 litres. 

STP stands for standard temperature and pressure. For STP conditions, the temperature is 273.15K (0

Pascals or 0.987 atm).

we will now use the relation

Here P

1

= 0.987 atm, V

1

= 44.8 litres, T

1

= 273.15 K, P

= 200K and V2 has to be calculated. Substituting these values in the above expression, we get

 [0.987 X 44.8] / 273.15 = [8.21 X V

 This gives us V