calculate the volume occupied by 2.8 gm of N2at STP
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So let us first find out the number of moles....... So N2 = 2*14 = 28 g/mol. (2.8 / 28 )moles = 0.1 mole. So the gas will occupy a volume of 0.1 * 22.4 = 2.24 L of volume.
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4
Answer:
N2 = 2*14 = 28 g/mol. (2.8 / 28 )moles = 0.1 mole. So the gas will occupy a volume of 0.1 * 22.4 = 2.24 L of volume.
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