Question

Calculate the volume occupied by 2.8g of Nitrogen at STP

Answer 1

if 14 grams of Nitrogen contains 22.4 litres then 2.8 grams contains is equals to question mark 22.4 x 2.8 division 14 is equals to 4.48 litres

Answer 2

Answer:

Now at S.T.P 28 grams of nitrogen gas has a volume of 22.4 litres. Thus 2.8 grams of nitrogen gas has a volume of 2.8×22.4/28=2.24 litres.

Explanation:

Given: 2.8 grams of nitrogen gas.

To find:

We have to find the volume at S.T.P.

Solution:

To determine the volume of 2.8 grams of nitrogen gas at S.T.P we have to follow the below steps as follows-

The atomic weight of nitrogen is 14 grams.

Thus, the molecular weight of nitrogen gas is 14×2=28 grams.

Now at S.T.P 28 grams of nitrogen gas has a volume of 22.4 litres.

Thus 2.8 grams of nitrogen gas has a volume of 2.8×22.4/28=2.24 litres.

Thus 2.8 grams of nitrogen gas has a volume of 2.24 litres at S.T.P

How do you calculate the volume of nitrogen gas at STP?

Multiply the coefficient 0.022414 by the number of moles to calculate the gas volume (in cubic meters) at the standard temperature and pressure. In our example, the volume of the nitrogen gas is 0.022414 x 2 = 0.044828 cubic meters or 44.828 liters

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