Question

Calculate the volume occupied by 2 moles of a vanderwaal gas at 5 atm 800 K
Given : a = 4.0 atm e? mor2, b = 0.0625 emor? R = 0.08 l-atm/K-mol

Answer 1

Answer:

n=0.2 mol, temp =T=298k P=0.0821 atm

a=4.105 and b=

6

1

Lmol

−1

[P+

V

2

n

2

a](V−nb)=nRT

⇒[0.0821+

V

2

0.04

(4.105)](V−0.2×

6

1

)=0.2×0.082×298

⇒[0.0821+

V

2

0.1642

](V−0.033)=4.8872

⇒ Volume required V=59.5268 Litres.