Calculate the volume occupied by 28 u Nitrogen gas.
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Atomic mass of Nitrogen is 28...
..1 mole of nitrogen gas at STP occupies = 22.4 l
or 6.022*10^23 molecules of nirogen occupies = 22.4l
1 molecule of nirtogen occupies = 22.4l/6.022*10^23 = 3.72*10^(-23) litre
So 28u of nitrogen will occupy 3.72*10^(-23) litre
..1 mole of nitrogen gas at STP occupies = 22.4 l
or 6.022*10^23 molecules of nirogen occupies = 22.4l
1 molecule of nirtogen occupies = 22.4l/6.022*10^23 = 3.72*10^(-23) litre
So 28u of nitrogen will occupy 3.72*10^(-23) litre
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