Question

calculate the volume occupied by 28u nitrogen gas​

Answer 1

Answer:

3.71*10power-23L

Explanation:

molecular mass of nitrogen =28u.

28u nitrogen gas=1molecules of N

1mole of nitrogen gas at stp occupies=22.4L

that means6.023*10power23molecules of N occupies=22.4L

hence,28u occupies=22.4/6.023*10power23

=3.71*10power-23