Calculate the volume occupied by 28u nitrogen gas
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molecular mass of nitrogen gas = 28u
28u nitrogen gas will contain 1 molecule of nitrogen.
1 mole of nitrogen gas in stp occupies = 22.4 litre
∴ 6.022*10²³ molecules of nirogen occupies = 22.4litre
1 molecule of nirtogen occupies = 22.4l/6.022*10²³ = 3.72*10⁻²³ litre
1.28 u represents the molecular mass of N₂ gas
∴Volume occupied by 1 mole of N₂ gas at stp =22.4 litre
28u nitrogen gas will contain 1 molecule of nitrogen.
1 mole of nitrogen gas in stp occupies = 22.4 litre
∴ 6.022*10²³ molecules of nirogen occupies = 22.4litre
1 molecule of nirtogen occupies = 22.4l/6.022*10²³ = 3.72*10⁻²³ litre
1.28 u represents the molecular mass of N₂ gas
∴Volume occupied by 1 mole of N₂ gas at stp =22.4 litre
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Unified mass of nitrogen is 1.28 or 28?
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