Question

Calculate the volume occupied by 3.2 grams of oxygen at 76 cmHg and 27°C. Answer in cc

Answer 1

Answer:

Volume occupied by the volume is 2.46 L.

Average kinetic energy of oxygen gas molecule is 6.21\times 10^{-23} J6.21×10

−23

J

Explanation:

Pressure of the oxygen gas,P = 76 cmHg=760 mmHg = 1 atm

Moles of oxygen gas ,n=\frac{3.2 g}{32 g/mol}=0.1 mol

32g/mol

3.2g

=0.1mol

Temperature of the oxygen gas = 27°C = 300 K

Volume occupied by the oxygen = V

PV=nRTPV=nRT

V=\frac{0.1 mol\times 0.0820 atm L/mol K\times 300 K}{1 atm}=2.46 LV=

1atm

0.1mol×0.0820atmL/molK×300K

=2.46L

Average kinetic energy of oxygen gas molecule:\frac{3K_b\timesT}{2}

2

3K

b

\timesT

E=\frac{3\times 1.380\times 10^{-23}J /K\times 300 K}{2}=6.21\times 10^{-23} JE=

2

3×1.380×10

−23

J/K×300K

=6.21×10

−23

J