Question

Calculate the volume occupied by 320 g of sulphur dioxide at STP. When S = 32 and O = 16.

Answer 1

molar mass = 64g occupies volume of 24 dm^3
vol. 320 g =24( 320/64)
= 24*5
120 dm^3

Answer 2

Molar Mass

=SO2

=32+16*2

=64

Mole of SO2= 320/64 = 5

1 mole = 22.4 litres

5 moles = 22.4 * 5 = 112.0 litres

Hence,

Answer= 112 litres