Calculate the volume occupied by 320 gram of sulphur dioxide at stp.
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I mol SO2 = 64 g
22.4 L SO2 = 64 g ( since, 1 mole = 22.4 l)
64 g = 22.4 l
320 g = (22.4/64 )*320
= 112 L
Hope you understood
22.4 L SO2 = 64 g ( since, 1 mole = 22.4 l)
64 g = 22.4 l
320 g = (22.4/64 )*320
= 112 L
Hope you understood
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