Question

Calculate the volume occupied by 4.045 x 10^23 molecules of oxygen at 27°C and having a pressure of
0.935 bar​

Answer 1

Answer:

Explanation:given that molecules no. Of oxygen is 4.045×10^23

Moles of oxygen - 4.045×10^23/6.023×10^23

Pv= nrt

O.935×v = 4.045×0.082×300÷6.02

V = 99.57/5.62= 17.71