Calculate the volume occupied by 4.2g of nitrogen at STP
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3
Answer:
moles of nitrogen= given mass/molecular mass
=4.2/28=0.15
Volume occupied by 1 mole of nitrogen at stp=22.4 l
Volume of 0.15 moles of nitrogen= 22.4×0.15= 3.36l
Explanation:
Answered by
2
Answer:
Explanation:
moles of nitrogen= given mass/molecular mass
=4.2/28=0.15
Volume occupied by 1 mole of nitrogen at stp=22.4 l
Volume of 0.15 moles of nitrogen= 22.4×0.15= 3.36l
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