Question

Calculate the volume occupied by 4.2g of nitrogen at STP

Answer 1

Answer:

moles of nitrogen= given mass/molecular mass

=4.2/28=0.15

Volume occupied by 1 mole of nitrogen at stp=22.4 l

Volume of 0.15 moles of nitrogen= 22.4×0.15= 3.36l

Explanation:

Answer 2

Answer:

Explanation:

moles of nitrogen= given mass/molecular mass

=4.2/28=0.15

Volume occupied by 1 mole of nitrogen at stp=22.4 l

Volume of 0.15 moles of nitrogen= 22.4×0.15= 3.36l