Question

calculate the volume occupied by 48g of Co2 at 290 kelvin and 715 mm Hg pressure

Answer 1

Explanation:

Moles of Nitrogen = Weight / Molar mass

= 7 g / (28 g/mol)

= 0.25 mol

Pressure = 750 mm Hg

= (750/760) atm ………[∵ 1 atm = 760 mm Hg]

= 75/76 atm

From ideal gas equation

V=

P

nRT

=

(75/76atm)

0.25mol×0.0821atm.L/(molK))

×300K

=6.2396 liters

The volume occupied by the gas is 6.2396 litres