Question

Calculate the volume occupied by 5.8 g of dioxygen at 32⁰ C and I bar pressure.

( R = 0.083 L bar mol – 1 K

– 1 ) (​

Answer 1

Answer:

PV = nRT

V=nRT ÷P

Mole = Given mass ÷ Molar mass

=3.5 ÷ 32 = 0.11 mol

R = 0.0821 L atm K

−1

mol

−1

T = 300K

P = 740 mm Hg = 0.973 atm (760 mm Hg = 1atm)

V = 0.11 x 0.0821 L atm K

−1

mol

−1

x 300K ÷ 0.973 atm

2.27